Bob's average golf score at his local course is 93.6 from a random sample of 34 rounds of golf. Assume that the population standard deviation for his golf score is 4.2. The 90% confidence interval around this sample mean is:. a. (92.4, 94.8).
b. (89.0, 98.3).
c. (90.5, 96.7).
d. (93.2, 94.0).

a. (92.4, 94.8)

Step-by-step explanation:

Given that:

Mean (m) = 93.6

Standard deviation (σ) = 4.2

Sample size (n) = 34

α = 90%

Confidence interval around sample mean :

Mean ± Zstatistic * s/√n

Z0.90 = 1.645 (Z probability calculator)

s / √n = 4.2 / √34 = 0.7202940

Lower limit = 93.6 - (1.645 * 0.7202940) = 92.41511637 = 92.4

Upper limit = 93.6 + (1.645 * 0.7202940) = 94.78488363 = 94.8

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.

step-by-step explanation: