$650,000 was stolen from 1st Trust American Bank during a heist. The bank robbers got away clean and sped away traveling at a constant rate of 70 miles per hour. What the robbers did not realize is that one of the bank bags had a GPS tracking device inside of it. Once the police locked on to the signal of the tracking device they took off after the robbers traveling at a constant rate of 90 miles per hour. If the robbers already had a 30 mile head start, how long will it take the police to pass them and force them off the road to be arrested?

The time taken before the police force the robbers off the road is 1.5 hours

Step-by-step explanation:

The speed with which the robbers were travelling = 70 miles per hour

The speed with which the police went after the robbers = 90 miles per hour

The distance with which the robbers were in front of the police before the police came after them =  miles

Let t represent the time in hours the police force the robbers off the road, we have;

30 + 70 × t = 90 × t

30 = 90 × t - 70 × t = (90 - 70) × t = 20 × t

30 = 20 × t

20 × t = 30

t = 30/20 = 1.5

t = 1.5 hours

The time taken before the police force the robbers off the road = t = 1.5 hours

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

6/20

step-by-step explanation: