A rock is thrown from the top of a ladder. The function h(t) = –16t2 + 120t + 10 gives the height of the rock t seconds after it is
thrown a certain number of feet.
What is the height of the rock at 5 seconds?

h'(t)=88

Step-by-step explanation:

h'(t)=d/dt (-16t x 2 + 120t + 10

h'(t)=d/dt (-32t + 120t + 10)

h'(t)=d/dt (88t + 10)

h'(t)=d/dt (88t) + d/dt (10)

h'(t)=88 + 0

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

answer: ur mum is gay