Find angle 1

(5x+6)° and (7x-18)°

Step-by-step explanation:

<1 is the supplement of 5x + 5.  You have to assume that the almost horizontal lines are parallel. In addition, two angles on the same side of a transversal across two parallel lines and are interior angles are supplementary.

5x + 6 + 7x - 18 = 180                   Add  like terms

12x - 12 = 180                                Add 12 to both sides

12x = 180 + 12

12x = 192                                      Divide by 12

x = 192 /12

x = 6

5x + 6 = 5*12 + 6

5x + 6 = 60 + 6

5x + 6 = 66

<1 + 66 = 180

<1 = 180 - 66

<1 = 114

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