1 pts There are 11 pets in a cute pet competition, 6 cats(C), 3 dogs(D) and 2 gerbils(G).
Three winners will be chosen for first second and third prize. A winner can only get
one prize. Sample space is (C1, C2, C3, C4, C5, C6, D1, D2, D3, G1, G2]
a) What is the probability that C5, G2 and D1 are chosen in that order?
b) What is the probability that all three chosen are C?
a) 990 b) a = 0.12
O a) 165 b 0.55
O a) 165 b) 0.12
a) 990 b 0.55

answer: add the !

step-by-step explanation: then we will answer

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder