How do I do this I'm confused

The interior angles of any triangle equal 180. Triangle CDF is an equilateral triangle meaning all of its angles are the same. 180/3=60

Each angle of triangle CDF is 60

1.m<CDF=60

Isosceles triangles have the 2 base angles the same value while the other angle is another value. IN that instance, the m<a = m<f and the m<a + m<f +  m<b=180°

If we find one of the angles of ABF then we can find all of them.

the m<AFB + 35° + m<CFD + m<DFE=180°

we know that the m<CFD is 60

35+60+m<AFB + m<DFE=180

95+m<AFB + m<DFE=180

LEts look at the angle AFD

AFD is 150° and since m<AFD and the m<DFE are supplementary, the angle of DFE is 30

lets test it:

if m<DFE is 30 then

95+m<AFB + 30=180

125+m<AFB=180

m<AFB=55

therefore the m<BAF would also be 55 and the m<ABF would be 70

m<ABF=70

This is because the interior angles of any triangle add up to 180°

I hope this helps and please let me know if i was incorrect

Step-by-step explanation:

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step-by-step explanation:

step-by-step explanation:

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