The number of pieces of candy in randomly selected jars are 20, 1, 29, 21, 40, 52, 41, 44, 60, 67. Display the data using a histogram.
A Pieces of Candy in Jars
C.
Pieces of Candy in Jars
Ques
bonbon
***
1-20 21-40 41-60 61-80
Pieas of code
1-20 21-40 41-60 61-80
Peasofandi
B.
D.
Pieces of Candy in Jars
Pieces of Candy in Jars
Que
Lubare
Frequency
61-30
1-20 21-40 41-60 61-80
Pieces of candy
1-20 21-40 450
Pieces of candy

4 + 5 7/9= 9 7/9

step-by-step explanation:

d

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240