There were about 340,000 cattle placed on feed. write an equivalent ratio that could be used to find how many of these cattle were between 700- 799 pounds. how many of the 340,000 cattle placed on feed were between 700-799 pounds?
weight group. fraction of total cattle
less than 600. 1\5
pounds.
600-699. 11/50
700-799. 2\5
800. 9\20

The correct answer is:

An equivalent ratio would be 4/10, and the number of cattle would be 136,000.

Explanation:

The question asks for an equivalent ratio. This means a fraction that is equivalent to the fraction between 700-799, which is 2/5.

To create an equivalent fraction, we multiply the numerator and denominator by the same number. Multiplying both by 2, we get

(2*2)/(5*2) = 4/10.

Tenths are useful when dealing with thousands, because taking a tenth involves getting rid of a zero. This means that 1/10 would be 34000; 4/10 would be 4 times that: 4(34000) = 136000.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

i think the answer is b x = 1, y = 35/2