What are the possible numbers of positive, negative, and complex zeros of f(x) = -x6 + x5 - x4 + 4x3 - 12x2 + 12? A. Positive: 4, 2, or 0; negative: 2 or 0; complex: 6, 4, 2, or 0
B. Positive: 3 or 1; negative: 3 or 1; complex: 4, 2, or 0
C. Positive: 2 or 0; negative: 2 or 0; complex: 6, 4, or 2
D. Positive: 5, 3, or 1; negative: 1; complex: 4, 2, or 0

bn

Step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions