Two sides of a parallelogram are represented by me qua ons y = 2x + 1 and y = -x + 3. Give two equations that can represent te other two sides. I dont know this pls help i have until december 13 2020

The value of  x  = 5 and y = 2.

Step-by-step explanation:

Here the DECK given is a parallelogram.

KT = 2x + y, DT = x + 2y, TE = 12 and TC = 9 are also

In a parallelogram, now:

DIAGONALS IN A BISECT OF A PARALLELOGRAM EACH OTHER

Even, in a DECK parallelogram,

The DC and KE sides have two diagonals.

T is the AC and KE mid-point.

· KT = TE and DT = TC ( as diagonals are bisected)

Approximately 2 x + y = 12 and x + 2y = 9

Here then the set of two equations is:

Two x + y = 12 x + 2 y y = 9

Multiply (2) by -2 and add (1), and we get: 2 x + y - 2 x - 4 y = 12 - 18 = 12 - 18 y

Or, - 3 y = - 6

Or or, y = 2

If y = 2, x + 2 (2) = 9, or x = 5, x = 5,

Consequently, the values of x = 5, y = 2 = 2

answer: kljdcdhjbdlchjad oac apoich a

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)