How much fertilizer containing 30% nitrogen should be mixed with a fertilizer containing 10% nitrogen to get 10L of a fertilizer containing 12% nitrogen?

1L of 30% fertilizer and 9L of 10% fertilizer

Step-by-step explanation:

Let x = the amount of fertilizer containing 30% nitrogen.

Let y = the amount of fertilizer containing 10% nitrogen

x + y = 10 because the two fertilizers together will be 10L

0.3x will be the amount of nitrogen in the 30% nitrogen fertilizer, and 0.1y will be the amount of nitrogen in the 10% fertilizer. If you add those together, you will get 12% of the nitrogen in the 10L mixture. This makes this equation:

0.3x + 0.1y = 0.12(10)

0.3x + 0.1y = 1.2

Now we have our two equations.

x + y = 10

0.3x + 0.1y = 1.2

We can use substitution to solve this system of equations.

x = 10 - y

Substituting this into the second equation, we have:

0.3(10-y) + 0.1y = 1.2

3 - 0.3y + 0.1y = 1.2

3 - 0.2y = 1.2

1.8 = 0.2y

9 = y

10 - 9 = 1L

There will be 9L of 10% nitrogen fertilizer and 1L of 30% nitrogen fertilizer.

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation:

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|