Determine if the vertex of the graph is a maximum point or a minimum point
1. y= -(x+1)^2
2. y= 2(x+1)^2 +1
3. y= -4/5(x+5)^2 -1

1. Maximum

2. Minimum

3. Maximum

Step-by-step explanation:

if a is positive, the graph opens up and has a minimum

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

the rate of change is 25