Mrs. Kudra invested $1000, part at 5% and the rest at 6.5%. She earned $59 in interest. How much was invested at the 5%? HELP PLEASE

f(x) is   are being squared

g(x) is   increasing by 2

h(x) is adding .25 each time

k(x) is taking the square root

f(x) and k(x) are exponential functions

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7

you need to know that the corresponding sides and angles are the same.

step-by-step explanation:

which statement is true about the local minimum of the graphed function?

over the interval [–4, –2], the local minimum is 0.

over the interval [–2, –1], the local minimum is 25.

over the interval [–1, 4], the local minimum is 0.

over the interval [4, 7], the local minimum is -7.