Line segment AC is given by A (-3,6) and B (6,9). Find the coordinates of point B such that AB:BC is 2:1 Please help now

(0, 7)

Step-by-step explanation:

Using the midpoint formula expressed as;

M (X, Y )= [(ax1+bx2/a+b), (ay1+by2/a+b)]

where a and b are the ratios

Given

a = 2

b = 1

x1 = -3

y1 = 6

x2 = 6

y2 = 9

Get the coordinate of B

Get X;

X = ax1+bx2/a+b

X = 2(-3)+1(6)/2+1

X = -6+6/3

X = 0/3

X = 0

Get Y;

Y = ay1+by2/a+b

Y = 2(6)+1(9)/2+1

Y = 12+9/3

Y = 21/3

Y = 7

Hence the coordinate of B is (0, 7)

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

do your own work and don"t cheat.

step-by-step explanation: