Construct a quadratic function that has a vertex at (−2,3) and includes the value (−1) = 1.

Vertex form of a quadratic equation is y=a(x-h)2+k, where (h,k) is the vertex of the parabola.

The vertex of a parabola is the point at the top or bottom of the parabola.

'h' is -6, the first coordinate in the vertex.

'k' is -4, the second coordinate in the vertex.

'x' is -2, the first coordinate in the other point.

Step-by-step explanation:

hope this help

pick me as the brainliest

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.