What is the equation of the line that passes through the point (2, -1) and has a
slope of 3/2

y = 3/2x - 4

Step-by-step explanation:

y = mx + b

*plugging in slope*

y = 3/2x + b

*finding b (aka y-intercept, starting value, when x=0) by plugging in x and y values from point (2, -1) )*

-1 = 3/2 * 2 + b

-1 = 3 + b

b = -4

so: y = 3/2x - 4

Given :-

A line having a slope of 3/2 passes through (2,-1) .

To Find :-

The equation of the line .

Answer :-

According to the question ,

m = 3/2

Point = (2,-1)

We know Point slope form of the line as ,

y - y¡ = m ( x - x ¡ )

Substitute ,

y - (-1) = 3/2 ( x - 2 )

y + 1 = 3/2x - 3/2*2

y +1 = 3/2x - 3

2( y +1) = 3/2x *2 - 3*2

2y + 2 = 3x - 6

3x -2y -8 = 0

1 1/5

step-by-step explanation:

answer: what do you mean