Solve each equation for 0 degrees < x < 360 degrees. Sqrt 2 cos x + 1 = 0

A.45,315
B.115,245
C.135,225
D.46, 314

Please Help ASAP!

120 degrees and 330 degrees

Step-by-step explanation:

Solve each equation for 0 degrees < x < 360 degrees.

Sqrt 2 cos x + 1 = 0

A.45,315

B.115,245

C.135,225

D.46, 314

Please Help ASAP!

Given the expression √(2cosx+1) = 0

Square both sides of the equation;

√(2cosx+1) = 0

2cosx + 1 = 0

2cosx = -1

cos x = -1/2

x = cos^-1(-1/2)

x = -60 degrees

Since cos is negative in the 2nd and 3rd quadrant then;

x = 180-60 = 120 degrees (2nd quadrant)

x = 270+60 = 330 degrees (3rd quadrant)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1