Consider three consecutive odd integers. The ratio of the smallest number to one less than twice the smallest number is equivalent to the ratio of three more than the middle number to twice the largest number. What are
the three integers?

Let x be the smallest of the three integers. Then the next two are x + 2 and x + 4.

• "The ratio of the smallest number to 1 less than twice the smallest number..."

This translates to

x / (2x - 1)

• "... the ratio of 3 more than the middle number to twice the largest number."

This translates to

((x + 2) + 3) / (2 (x + 4))

or, simplifying a bit,

(x + 5) / (2x + 8)

The ratioes are said to be equivalent, so

x / (2x - 1) = (x + 5) / (2x + 8)

Solve for x :

x (2x + 8) = (x + 5) (2x - 1)

2x² + 8x = 2x² + 9x - 5

8x = 9x - 5

-x = -5

x = 5

So the three integers are 5, 7, and 9.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

i dont know the answer but here's a picture of a dog