A jar contains n nickels and d dimes. There are 22 coins in the jar, and the total value of the coins is $1.45. How many nickels and how many dimes are in the jar? (Hint: Nickels are
worth $0.05 and dimes are worth $0.10.)
There are
nickels and
dimes in the jar.

7 dimes and 15 nickels

Step-by-step explanation:

Let n = number of nickels

d = number of dimes

The value of all the nickels is .05n since each nickel is worth 5 cents and

the value of all the dimes is .10d since each dime is worth 10 cents

Now    n + d = 22    and .05n + .10d = 1.45

          d = 22 - n                  5n + 10d = 145

                                            5n + 10(22 - n) = 145

                                       5n + 220 - 10n = 145

                                               -5n = -75

                                                  n = 15 nickels

           d = 22 - 15 = 7 dimes

Check:  All the nickels are worth 75 cents and all the dimes are worth 70 cents.   75 + 70 = 145 cents or $1.45

c. 4 1/4 pounds

i think the answer is c sorry if it's wrong