How many centimeters long is a leg of an isosceles right triangle if its hypotenuse has a length of 8√2 centimeters? Please help :

Thanks

The leg is 8 cm long

Step-by-step explanation:

An isosceles right triangle has the length of its hypotenuse and opposite equal

Let us call the length x

From Pythagoras’ , the square of the hypotenuse equals the sum of the squares of the two other sides

Thus, we have ;

x^2 + x^2 = (8 √2)^2

2x^2 = 128

x^2 = 128/2

x^2 = 64

x= √64

x = 8 cm

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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