A ball at the end of a 2 meter string revolves in a circle at a rate of 4 m/s. What is the centripetal acceleration of the ball?

8 m/s^2

Step-by-step explanation:

You can use the equation a = v^2 / r

That is acceleration is equal to velocity squared divided by the radius which in this problem is the length of the string. The velocity is 4m/s and the r the radius is 2 m. Now you can square 4 m/s to get 16 m^2/s^2 THEN you divide by 2 m and the m^2 turns to just m and the 16 to an 8. So, that leaves you with acceleration or in this case centripetal acceleration equals 8 m/s^2.

a = 8 m/s^2     or  8 meters per second squared.

-2/

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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