Can you please help me I need help with this question it’s for my test

y=3

Step-by-step explanation:

Assuming this is an enlargement where EFGH is enlarged to ABCD then the former is the object and the latter is the image. If so then

scale factor(k) of the enlargement=image length/corresponding object length

k=3/2

Therefore, y=4.5/k

y=4.5/(3/2)

y=3

If we take the assumption another way and say ABCD is reduced to EFGH then the former is the object and the latter is the image.

In that case,

k=⅔

y=4.5×k

y=3

In either case y=3units

ege

step-by-step explanation:

egge

it is probably the graph on the bottom right.