A bouncy ball is dropped such that the height of its first bounce is 7.25 feet and each successive bounce is 70% of the previous bounce's height. What would be the height of the 7th bounce of the ball? Round to the nearest tenth (if necessary).

The height of the 7th bounce of the ball is 0.90 feet.

Step-by-step explanation:

Given that he successive bounce is 70% of the previous bounce's height, the;

the first bounce height = 7.25 feet

the 2nd bounce height = 7.25 x 0.7

                                       = 5.075 feet

the 3rd bounce = 5.075 x 0.7

                        = 3.5525 feet

the 4th bounce = 3.5525 x 0.7

                          = 2.48675 feet

the 5th bounce = 2.48675 x 0.7

                          = 1.740725 feet

the 6th bounce = 1.740725 x 0.7

                           = 1.2185075 feet

the 7th bounce = 0.85295525 feet

Thus, the height of the 7th bounce of the ball is 0.90 feet.

after simplifying it i got: -36.25 as my answer. hope that !

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer