A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, . y=-16x^2+261x+130

Step-by-step explanation:

Given the maximum height of the rocket modelled by the expression

y=-16x^2+261x+130

The rocket velocity at its maximum height is zero.

v(x) = dy/dx = 0

dy/dx = -32x + 261

0 = -32x + 261

32x = 261

x = 261/32

x= 8.156secs

Substitute the time into the given expression'

y=-16(8.16)^2+261(8.16)+130

y = -1,064.88 + 2,129.76 + 130

y = 1194.88

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

ok so what's the question?

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