Mathematics, 09.12.2020 22:30 Kimmie2019

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1 A. f(x) = −1/12(x − 5)^2 + 2
B. f(x) = 1/12(x − 5)^2 + 2
C. f(x) = −1/12(x + 5)^2 + 2
D. f(x) = 1/12(x + 5)^2 + 2

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Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1 A. f(x) = −1/...

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Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1 A. f(x) = −1/12(x − 5)^2 + 2 B. f(x) = 1/12(x − 5)^2 + 2 C. f(x) = −1/12(x + 5)^2 + 2 D. f(x) = 1/12(x + 5)^2 + 2

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Another question on Mathematics

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1 A. f(x) = −1/12(x − 5)^2 + 2
B. f(x) = 1/12(x − 5)^2 + 2
C. f(x) = −1/12(x + 5)^2 + 2
D. f(x) = 1/12(x + 5)^2 + 2