According to a report in USA Today, more and more parents are helping their young adult children buy homes. You would like to construct a 90% confidence interval of the proportion of all young adults in Louisville, Kentucky, who received help from their parents in buying a home. How large a sample should you take so that the margin of error is no more than 0.06?

The value is

Step-by-step explanation:

From the question we are told that

    The margin of error is  

From the question we are told the confidence level is  90% , hence the level of significance is    

=>  

Generally from the normal distribution table the critical value  of   is  

  Generally will assume that the sample proportion young adults in Louisville, Kentucky, who received help from their parents in buying a home is  

Generally the sample size is mathematically represented as  

=>  

=>  

765238725478629038640962136509762139056074

step-by-step explanation:

64087235609746097215074621039754021037