A large aquarium should contain 10,000 liters of water when it is filled correctly. Fish will get sick if the aquarium gets down to 4,000 liters or less. One day over the weekend, there is an accident, and the tank cracks in 4 places, causing water to empty out of the aquarium at a rate of 20.5 liters per hour. The aquarium workers did not catch the leaks until 2 days later. How much water was left in the tank when the aquarium workers finally caught the leak? Based on the level of water, were fish sick?

9016 litres left

Step-by-step explanation:

The fish were not sick.

You would multiply 20.5 by 48 which is the amount of hours in 2 days then subtract that amount from 10000 to see how much is left

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;