Help me with this please

A baseball diamond is a square with sides of 90 feet. What is the distance to the nearest tenth of a foot between home and second base?

Step-by-step explanation:

127.3 feet This problem requires the use of pythagoras theorem. Ignore the face that it's a baseball diamond. All you're concerned with is that you have a square that's 90 feet per side and you want to know what the length of the diagonal. So you have a right triangle with 2 sides of 90 feet each and you want to know the length of the hypotenuse. The formula is C^2 = A^2 + B^2 Both A and B are 90, so plugging them into the formula gives C^2 = 90^2 + 90^2 = 8100 + 8100 = 16200 So C^2 = 16200 Take the square root of both sides C = 127.2792 Round to the nearest tenth, giving C = 127.3

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.