What is the solution to the following system x+y+z=6 and x-y+z=8 and x+y-z=0

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Step-by-step explanation:

(eq-1) → x + y + z = 6

(eq-2) → x - y + z = 8

(eq-3) → x + y - z = 0

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Eliminate eq-1 and eq-3

x + y - z = 0    

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Eliminate eq-1 and qe-2

x - y + z = 8    

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Substitute the value of z and y to on of equations

The solution for the following system is:

Step-by-step explanation:

We need to find the solution to the following system.

Let:

Adding eq(1) and eq(2)

Adding eq(2) and eq(3)

We get value of x=4

Now, putting value of x in eq(4) to find value of z

We get value of z=3

Now, putting value of x and z in eq(1) to find value of y

So, value of y=-1

The solution for the following system is:

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c