A stone is thrown up from the ground, the trajectory of the stone can be described as h(t) = −6t^2 + 18t, where t is the time in seconds after the throw and h is a height (in feet) of the stone above the ground.
(a). When does the stone reach its maximum height? What is the maximum height that the stone would
reach?
(b). How long will it take to hit the ground?

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d

the answer is

d.

5.3066 m2

step-by-step explanation: