What is an equation of the line that passes through the points (-6,-5) and (-4,-6)? Put your answer in fully redued form.

y=-5/2x-16

Step-by-step explanation:

1. Find the slope using the slope formula and the two coordinates provided.

m=y2-y1/x2-x1

Put the y values from both coordinates on top and the x values on bottom.

-6--5/-4--6

Solve for M. -6--5/-4--6 = -6+1/-4+6

= -5/2

Slope is -5/2.

2. Using the slope and one of the coordinates (doesn't matter which), put the equation in point-slope form: y-y1=m(x-x1)

y+6=-5/2(x+4)

3. Distribute the -5/2 to x+4 and simplify (multiply x and 4 by -5/2)

y+6=-5/2x-10

Subtract 6 from both sides to get y by itself.

y=-5/2x-16

4. y=-5/2x-16 is your answer

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2