Mathematics, 09.12.2020 02:10 dondre54
Johanna sells small cakes for $60 and large cakes for $80. She earned $1200 in sales one day. Johanna found that she could represent this situation with the equation
I'LL GIVE YOU BRAINLIEST IF YOU HELP ME FOREAL DON'T ASK IF YOU ARE JUST WRITING STUFF FOR THE POINTS
60x+80y=1200
where x is the number of small cakes and y is the number of large cakes.
If this equation is rewritten as a function by solving for y, what would be a reasonable domain for that function?
Answers: 1
Mathematics, 21.06.2019 12:50
Radii ok and nl are perpendicular to om because of the radius-tangent theorem. by definition of perpendicular, angles kom and lnm are right angles. this means that triangles kom and lnm are right triangles. angle lmn is common to both right triangles, so by the triangles kom and lnm are similar.
Answers: 2
Mathematics, 21.06.2019 17:00
During your cycling trip, you and your friends often stayed in hostels. the prices of these are listed below. hostel standard room (price per night) with breakfast (price per night) super sleep hostels Ā£22.45 Ā£28.65 normandy nights Ā£18.55 Ā£25 zzzola hostels Ā£24.50 Ā£30.99 belgian beds Ā£11.20 Ā£18.55 night-time rest days ? Ā£33 what is the range in cost for a single night, including both standard room prices and with breakfast prices?
Answers: 1
Mathematics, 21.06.2019 18:30
The lengths of two sides of a right triangle are given. find the length of the third side. round to the nearest tenth if necessary. a) y = 12/5x + 39/5 b) y = 5/12x + 5/39 c) y = 12/5x - 39/5 d) y = 5/12x - 5/39
Answers: 2
Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) ā sinh2(x) = 1 and (b) 1 ā tanh 2(x) = sech 2(x). solution (a) cosh2(x) ā sinh2(x) = ex + eāx 2 2 ā 2 = e2x + 2 + eā2x 4 ā = 4 = . (b) we start with the identity proved in part (a): cosh2(x) ā sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 ā sinh2(x) cosh2(x) = 1 or 1 ā tanh 2(x) = .
Answers: 3
Johanna sells small cakes for $60 and large cakes for $80. She earned $1200 in sales one day. Johann...
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