In a game a player wins if he rolls a 6 on a number cube if the number cube is rolled 18 times then what is an reasonable prediction for the number of unsuccsecful rollls

the reasonable prediction for the number of unsuccessful rollls is 15 ÷ 18

Step-by-step explanation:

The computation of the number of unsuccessful rolls is as follow:

For a number cube, the probability of getting 6 would be 1 ÷ 6 and for not getting is 5 ÷ 6

Now for 18 rolls i.e. there is 3 group of 6 so the chance of not getting would be 15 ÷ 18

Hence, the reasonable prediction for the number of unsuccessful rollls is 15 ÷ 18

The same is to be considered

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

i believe the answer is letter c) 8

step-by-step explanation: