Find the vertex.
4) y=-2x^2-8x-6

Vertex: (-2, 2)

Step-by-step explanation:

The x-coordinate of the vertex would be as follows;

x = -b/2a = 8/2(-2) = -8/4 = -2

respectively the y-coordinate of the vertex would be y(-2) = -2(-2)^2 - 8(-2) - 6 = -2(4) + 16 - 6 = - 8 + 10 = 2

Your vertex would be a maximum of (-2, 2)

* I say maximum as the coefficient of x^2 is -2, and it is less than zero so the parabola opens downward