A company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 23 components and accept the whole batch if there are fewer than 3 defectives. If a particular shipment of thousands of components actually has a 8% rate of defects, what is the probability of fewer than 3 defectives?

just needed some points but try socratic

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

2500

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1