3.(05.01) A pair of linear equations is shown below:
Y-2x + 3
Y-tx-1
Which of the following statements best explains the steps to solve
pair of equations graphically? (4 points)
O Graph the first equation, which has slope 3 and y-intercept = -2, graph the second equation, which has slope = -1 and y-intercept-4, and find the point of intersection of the two lines,
O Graph the first equation, which has slope = -3 and y-intercept2, graph the second equation, which has slope - 1 and y-intercept 4, and find the point of intersection of the two lines.
Graph the first equation, which has slope-2 and y-Intercept = 3, graph the second equation, which has slope -4 and y-intercept -1, and find the point of intersection of the two lines
O Graph the first equation, which has slope - 2 and y-intercept = -3, graph the second equation, which has slope - 4 and y-intercept = 1, and find the point of intersection of the two lines

C. Graph the first equation, which has slope = −2 and y-intercept = 3, graph the second equation, which has slope = −4 and y-intercept = −1, and find the point of intersection of the two lines.

Step-by-step explanation:

The two equations are in slope intercept form which is y = mx + b where m is the slope and b is the y-intercept.

In the first equation (y = -2x + 3), -2 is the slope since it is the coefficient. "b" is 3 since it is the constant of the equation.

In the second equation (y = -4x -1), -4 is the slope is the coefficient, and the y-intercept is -1 since it is the constant.

To solve the equations graphically, graph them and find the point where they intersect.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the correct answer is d

hope this