Line v passes through point [6.6] and is perpendicular to the graph of y= 3/4x - 11 line w is parallel to line v and passes through point [-6,10] what is the equation in slope intercept form of line w please help im in a exam

Given:

The equation of a line is

Line v passes through point (6,6) and it is perpendicular to the given line.

Line w passes through point (-6,10) and it is parallel to the line v.

To find:

The equation in slope intercept form of line w.

Solution:

Slope intercept form of a line is

        ...(i)

where, m is slope and b is y-intercept.

We have,

     ...(ii)

On comparing (i) and (ii), we get

So, slope of given line is .

Product of slopes of two perpendicular lines is -1.

Line w is perpendicular to the given line. So, the slope of line w is .

Slopes of parallel line are equal.

Line v is parallel to line w. So, slope of line v is also .

Slope of line v is and it passes thorugh (-6,10). So, the equation of line v is

where, m is slope.

Adding 10 on both sides, we get

Therefore the equation of line v is .

step-by-step explanation:

compare

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.