3) Kepler's third law states that the periodic time square (T2) of a planet's orbit around the Sun is directly proportional to the cube half the length of the largest axis of the planet's orbit (r ^ 3) . Where M is in kilograms, r is in meters, T is in seconds This law is known as the law of Periods. The square of the time period of the planet is directly proportional to the cube of the semi major axis of its orbit. T^ 2 propto a^ 3 That means the time 'T 'is directly proportional to the cube of the semi major axis i. e. 'a'. Let us derive the equation of Kepler's 3rd law. Let us suppose M = mass of the Sun in (kg),) r ( in (meters) and T are in seconds. T ^ 2 = (4Pi ^ 2)/((6.673)(10 ^ - 11) * M) * r ^ 3 Find half the length of the largest axis of the planet's orbit: Where M=6*10^ 24 kg and T = 5175 seconds

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

answer: 4 (:

step-by-step explanation:

k

step-by-step explanation:

domit