A line segment has endpoints (-4, -6) and (-6, 4). Which reflection will produce an image with endpoints at (4, -6) and (6, 4)

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

F(n + 1) = f(n) – 8. if f(1) = 100, what is f(6)?

Valentina is subtracting from . she finds the lcd to be 15y2. what is valentina's next step?