In a group of 39 pupils, 10 play the flute only. 1 plays the piano only.
13 play neither instrument.
A student is selected at random.
What is the probability the student plays both instruments?

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

i dont get the question

step-by-step explanation:

c

step-by-step explanation:

i need points

step-by-step explanation:

sorry bubs