Find 3 consecutive numbers who sum is 216

the three consecutive numbers be 71, 72 and 73 respectively

Step-by-step explanation:

The computation of the 3 consecutive numbers is shown below:

Let us assume the three consecutive numbers be x , x+1 and x + 2

Now their sum is

x + x + 1 + x+ 2 = 216

3x + 3 = 216

3x = 216 -3

3 = 213

x = 71

x + 1 = 71 + 1 = 72

x + 2 = 71 + 2 = 73

Hence, the three consecutive numbers be 71, 72 and 73 respectively

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