als den is 12 feet longer than it is wide. if the dens area is 405 square feet, what are the dimensions of the room?

The room has a length of 27 feet and width 15 feet.

Step-by-step explanation:

Given that:

Area of den = A = 405 square feet

Let,

L represent the length of room and W represent the width of room.

L = W+12

Area = Length * Width

Factorizing the equation

Either,

W-15 = 0

W=15

Or,

W+27=0

W=-27

As the width cannot be negative, therefore,

Width of den = 15 feet

Length of den = 15+12 = 27 feet

Hence,

The room has a length of 27 feet and width 15 feet.

a - base

b - exponent

so,

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13