A polynomial function upper P left parenthesis x right parenthesis with rational coefficients has the given roots. Find two additional roots of upper P left parenthesis x right parenthesis equals 0. negative 2 I and StartRoot 10 EndRoot
A. 2i, negative 10
B. 2i, 100
C. 2 i comma negative start root 10 end root
D. negative 2 comma negative 10

the olimpics is not going to wokk out

step-by-step explanation:

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110

there is only one way to arrange all the eight relative to each other because they are not distinct. we have

now there are nine places to place an (and not more than one in one place).   because we have four symbols, we need to choose four of these nine places to insert an . order does not matter because the are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."