In triangle $DEF,$ $\angle D = 30^\circ,$ $\angle F = 60^\circ,$ and $EF = 6.$ Find $DE + DF.$ [asy]
unitsize(2 cm);

pair D, E, F;

D = (0,sqrt(3));
E = (0,0);
F = (1,0);

draw(D--E--F--cycle);

label("$D$", D, N);
label("$E$", E, SW);
label("$F$", F, SE);
label("$6$", (E + F)/2, S);
[/asy]

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

5/20 so 25%

step-by-step explanation:

b

step-by-step explanation: