The middleweight division in wrestling is centered at 140 pounds. Deviation from that must be less than 15 pounds either way. Write and solve the Absolute value inequality. What is the range of the possible weights for the lightweight division?

125lb < M < 155 lb

Step-by-step explanation:

The mean mass is 140 lb, and the deviation must be less than 15 pounds (exactly 15 is not accepted).

Then (140lb + 15lb) is not alowed, and (140lb - 15lb) is not alowed.

Then we can define M = mass.

We have the two equations:

M < 140lb + 15lb

M < 155lb

And

M > (140lb - 15lb)

M > 125lb

If we write these two relations togheter, we get:

125lb < M < 155 lb

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;