A tortoise is moving at a rate of 2 feet per minute, while a hare is running at a rate of 8 feet per minute. If the tortoise had a head start of 180 feet, how long will it take for the tortoise and hare to meet? If the variables that represent the scenario are f for distance in feet and m for time in minutes, which equation represents the hare’s run?

f = 2m + 8m
f = 2m + 180
f = 8m + 180
f = 8m

Step-by-step explanation:

f = 8m. They are asking for the equation that represents the hare’s run, which they said “the hare is running at a rate of 8 feet per minute”, so f (the distance in feet) is equal to the 8 feet per minute that the hare runs.

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..