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Mathematics, 07.12.2020 22:50 maybe67

The equation of line LM is 5x βˆ’ y = βˆ’4. What is the equation of a line perpendicular to line LM in slope-intercept form that contains point (βˆ’3, 2)? y = 5x + 13 y = negative one fifthx + seven fifths y = negative one fifthx βˆ’ seven fifths y = 5x βˆ’ 17

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The equation of line LM is 5x βˆ’ y = βˆ’4. What is the equation of a line perpendicular to line LM in s...
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