The algebraic rules below show the cost, C, for printing n school yearbooks for two different companies, Speedy Printers: C = 29n
• On-time Printers: C = 100 +25n
If the number of yearbooks ordered is doubled, will the cost double? Provide an answer and justification for each
company

The cost will double for the speedy printer.

The cost will not double for one-time printer.

Given the cost, C, for printing n school yearbooks for two different companies, expressed as:

Speedy Printers: C = 29n

On-time Printers: C = 100 +25n

If the number of yearbooks ordered is doubled for the speedy printer, the new cost will be;

Cn = 29(2n)

Cn = 58n

Cn = 2(29n)

Cn = 2C

This shows that the cost will double for the speedy printer.

For one-time printer:

On-time Printers: C = 100 +25n

If the number of yearbooks is doubled, the new cost will be expressed as:

Cn = 100 + 25(2n)

Cn = 100 + 50n

Since we can not write the new cost as a function of the original cost, hence the cost will not double for one-time printer.

Learn more on cost functions here: link

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

i do not know the answer

step-by-step explanation: