What’s 2(b+3y+4z+7) if b=3 and y=6 and z=1

64

Step-by-step explanation:

You need to substitute the value of each number into its corresponding variable

2(3 + 3(6) + 4(1)+ 7)

You multiply to get this

2(3+18+4+7)

You then add all of the numbers up to get this

2(32)

Then, multiply 2 by 32 to get 64

b is the final answer! : )

c-4 is the final answer! : )