An object is dropped from a height of 100 meters. The function below models the relationship between t , the number of seconds after the object is dropped, and f(t) , the height of the object after it is dropped. f(t)=100−4.9t^2 Approximately how many seconds does it take for the object to hit the ground?

Step-by-step explanation:

Given

Required

Time it hits the ground

When the object hits the ground, the height is 0.

In other words:

f(t) = 0

So, we have:

Collect like terms

Divide through by 4.9

Take positive square roots of both sides

Hence, the ball hits the ground after 4.52 seconds

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.